Find Largest and Second Largest number in array

Given a integer array, find largest and second largest number in array

There are many approach to solve this problem, Lets see one of the efficient way.

Given a integer array, find largest and second largest number in array

**.****Lets understand the problem statement graphically and it will be more clear,**### Algorithm

There are many approach to solve this problem, Lets see one of the efficient way.

- Take 2 variable "max" and "secondMax" and initialize both to first element of array.
**int max = arr[0]**

int secondMax = arr[0] - Iterate through array and for each value of array, check,
- if the current value in array is > "max" then update "secondMax" with "max" value and "max" with new maimum value found.

- if the current value in array is < "max" but > then "secondMax" then update "secondMax" with new second largest element found
**.**

### Java Program to find Largest and Second Largest element in array.

public class FindSecondLargestNumberArray { public static void main(String[] args) { int[] arr = new int[]{1,1,3,1,5,4}; findLargestAndSecondLargestNumberArray(arr); } private static void findLargestAndSecondLargestNumberArray(int[] arr){ if(arr==null || arr.length < 2){ System.out.println("Invalid Input"); return; } int max = arr[0]; int secondMax = arr[0]; for (int value : arr) { if(value > max){ secondMax = max; max = value; }else if(max == secondMax || (value > secondMax && value != max)){ //value != max condition is required for [1,9,9] kind of array, //where secondMax is 1, but if we don't add this condition then //it will set secondMax not found. secondMax = value; } } if(secondMax == max){ System.out.println("Largest number : "+max); System.out.println("second largest number : not found"); }else{ System.out.println("Largest number : "+max); System.out.println("second largest number :"+secondMax); } } }

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**Enjoy !!!!**

**If you find any issue in post or face any error while implementing, Please comment.**

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